The electric field component of a monochromatic radiation is given by \[\vec{E}=2{{E}_{0}}\,\,\hat{i}\,\,\cos \,\,kz\,\cos \omega t\] Its magnetic field B is then given by:

\[\frac{2{{E}_{o}}}{c}\hat{j}\,\cos \,kz\,\cos \,\omega t\]

\[\frac{2{{E}_{o}}}{c}\hat{j}\,\sin \,kz\,\cos \,\omega t\]

\[-\frac{2{{E}_{o}}}{c}\hat{j}\,\sin \,kz\,\sin \,\omega t\]

\[\frac{2{{E}_{o}}}{c}\hat{j}\,\sin \,kz\,\sin \,\omega t\]

The electric field component of a monochromatic radiation is given by

1.	The electric field component of a monochromatic radiation is given by \[\vec{E}=2{{E}_{0}}\,\,\hat{i}\,\,\cos \,\,kz\,\cos \omega t\] Its magnetic field B is then given by:
A.	\[\frac{2{{E}_{o}}}{c}\hat{j}\,\sin \,kz\,\cos \,\omega t\]
B.	\[-\frac{2{{E}_{o}}}{c}\hat{j}\,\sin \,kz\,\sin \,\omega t\]
C.	\[\frac{2{{E}_{o}}}{c}\hat{j}\,\sin \,kz\,\sin \,\omega t\]
D.	\[\frac{2{{E}_{o}}}{c}\hat{j}\,\cos \,kz\,\cos \,\omega t\]
Answer» D. \[\frac{2{{E}_{o}}}{c}\hat{j}\,\cos \,kz\,\cos \,\omega t\]