1.

The edge of unit cell of FCC \[Xe\] crystal is \[620\,pm\]. The radius of \[Xe\] atom is      [MP PET 2004]

A.                 219.25 Pm          
B.                 235.16 Pm
C.                 189.37 Pm          
D.                 209.87 Pm
Answer» B.                 235.16 Pm


Discussion

No Comment Found

Related MCQs