The eccentricity of the hyperbola \[\frac{{{x}^{2}}}{16}-\frac{{{y}^{2}}}{25}=1\] is [Karnataka CET 2005]

The eccentricity of the hyperbola \[\frac{{{x}^{2}}}{16}-\frac{{{y}^

1.	The eccentricity of the hyperbola \[\frac{{{x}^{2}}}{16}-\frac{{{y}^{2}}}{25}=1\] is [Karnataka CET 2005]
A.	3/4
B.	3/5
C.	\[\sqrt{41}/4\]
D.	\[\sqrt{41/5}\]
Answer» D. \[\sqrt{41/5}\]

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The eccentricity of the hyperbola \[\frac{{{x}^{2}}}{16}-\frac{{{y}^{2}}}{25}=1\] is [Karnataka CET 2005]

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