The eccentricity of the hyperbola \[\frac{\sqrt{1999}}{3}({{x}^{2}}-{{y}^{2}})=1\] is [Karnataka CET 1999]

The eccentricity of the hyperbola \[\frac{\sqrt{1999}}{3}({{x}^{2}}-{{

1.	The eccentricity of the hyperbola \[\frac{\sqrt{1999}}{3}({{x}^{2}}-{{y}^{2}})=1\] is [Karnataka CET 1999]
A.	\[\sqrt{3}\]
B.	\[\sqrt{2}\]
C.	2
D.	\[2\sqrt{2}\]
Answer» C. 2

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The eccentricity of the hyperbola \[\frac{\sqrt{1999}}{3}({{x}^{2}}-{{y}^{2}})=1\] is [Karnataka CET 1999]

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