MCQOPTIONS
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| 1. |
The displacement of a particle varies with time as \[x=12\sin \omega t-16{{\sin }^{3}}\omega t\](in cm). If its motion is S.H.M., then its maximum acceleration is |
| A. | \[12\,{{\omega }^{2}}\] |
| B. | \[36\,{{\omega }^{2}}\] |
| C. | \[144\,{{\omega }^{2}}\] |
| D. | \[\sqrt{192}\,{{\omega }^{2}}\] |
| Answer» C. \[144\,{{\omega }^{2}}\] | |