The disintegration of an isotope of sodium. \[_{11}N{{a}^{24}}{{\to }_{12}}M{{g}^{24}}{{+}_{-1}}{{e}^{0}}\] shown is due to [AMU (Engg.) 2000]

The formation of a stable nuclide

The fall in the neutron : proton ratio

The disintegration of an isotope of sodium. \[_{11}N{{a}^{24}}{{\to }_

1.	The disintegration of an isotope of sodium. \[_{11}N{{a}^{24}}{{\to }_{12}}M{{g}^{24}}{{+}_{-1}}{{e}^{0}}\] shown is due to [AMU (Engg.) 2000]
A.	The emission of b-radiation
B.	The formation of a stable nuclide
C.	The fall in the neutron : proton ratio
D.	None of these
Answer» B. The formation of a stable nuclide

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The disintegration of an isotope of sodium. \[_{11}N{{a}^{24}}{{\to }_{12}}M{{g}^{24}}{{+}_{-1}}{{e}^{0}}\] shown is due to [AMU (Engg.) 2000]

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