The differential equation obtained on eliminating A and B from the equation \[y=A\cos \omega t+B\sin \omega t\] is [Karnataka CET 2000; Pb. CET 2001]

The differential equation obtained on eliminating A and B from the equ

1.	The differential equation obtained on eliminating A and B from the equation \[y=A\cos \omega t+B\sin \omega t\] is [Karnataka CET 2000; Pb. CET 2001]
A.	\[{y}''=-{{\omega }^{2}}y\]
B.	\[{y}''+y=0\]
C.	\[{y}''+{y}'=0\]
D.	\[{y}''-{{\omega }^{2}}y=0\]
Answer» B. \[{y}''+y=0\]

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The differential equation obtained on eliminating A and B from the equation \[y=A\cos \omega t+B\sin \omega t\] is [Karnataka CET 2000; Pb. CET 2001]

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