MCQOPTIONS
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| 1. |
The diameter of the objective of a telescope is a, its magnifying power is m and wavelength of light is \[\lambda .\]The resolving power of the telescope is [MP PMT 2000] |
| A. | \[(1.22\,\lambda )/a\] |
| B. | \[(1.22\,a)/\lambda \] |
| C. | \[\lambda m/(1.22a)\] |
| D. | \[a/(1.22\lambda \,)\] |
| Answer» E. | |