The derivative of \[{{\sin }^{-1}}\left( \frac{2x}{1+{{x}^{2}}} \right)\] with respect to \[{{\cos }^{-1}}\left[ \frac{1-{{x}^{2}}}{1+{{x}^{2}}} \right]\] is equal to:

The derivative of \[{{\sin }^{-1}}\left( \frac{2x}{1+{{x}^{2}}} \right

1.	The derivative of \[{{\sin }^{-1}}\left( \frac{2x}{1+{{x}^{2}}} \right)\] with respect to \[{{\cos }^{-1}}\left[ \frac{1-{{x}^{2}}}{1+{{x}^{2}}} \right]\] is equal to:
A.	1
B.	-1
C.	2
D.	None of these
Answer» B. -1

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The derivative of \[{{\sin }^{-1}}\left( \frac{2x}{1+{{x}^{2}}} \right)\] with respect to \[{{\cos }^{-1}}\left[ \frac{1-{{x}^{2}}}{1+{{x}^{2}}} \right]\] is equal to:

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