MCQOPTIONS
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| 1. |
The depth d at which the value of acceleration due to gravity becomes \[\frac{1}{n}\] times the value at the surface of the earth, is [R = radius of the earth] |
| A. | \[\frac{R}{n}\] |
| B. | \[R\left( \frac{n-1}{n} \right)\] |
| C. | \[\frac{R}{{{n}^{2}}}\] |
| D. | \[R\left( \frac{n}{n+1} \right)\] |
| Answer» C. \[\frac{R}{{{n}^{2}}}\] | |