The dehydrobromination of 2-bromobutane gives \[C{{H}_{3}}CH=CHC{{H}_{3}}.\] The product is

The dehydrobromination of 2-bromobutane gives \[C{{H}_{3}}CH=CHC{{H}_{

1.	The dehydrobromination of 2-bromobutane gives \[C{{H}_{3}}CH=CHC{{H}_{3}}.\] The product is
A.	Hofmann product
B.	Saytzeff product
C.	Hoffmann-Saytzeff product
D.	Markownikoff product
Answer» C. Hoffmann-Saytzeff product

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The dehydrobromination of 2-bromobutane gives \[C{{H}_{3}}CH=CHC{{H}_{3}}.\] The product is

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