The degree of the differential equation \[\left( \frac{2+\sin x}{1+y} \right)\frac{dy}{dx}=-\cos ,x\ y(0)=1,\] is [Pb. CET 2003]

The degree of the differential equation \[\left( \frac{2+\sin x}{1+y}

1.	The degree of the differential equation \[\left( \frac{2+\sin x}{1+y} \right)\frac{dy}{dx}=-\cos ,x\ y(0)=1,\] is [Pb. CET 2003]
A.	1
B.	2
C.	3
D.	6
Answer» C. 3

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The degree of the differential equation \[\left( \frac{2+\sin x}{1+y} \right)\frac{dy}{dx}=-\cos ,x\ y(0)=1,\] is [Pb. CET 2003]

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