The degree of differential equation satisfying the relation\[\sqrt{1+{{x}^{2}}}+\sqrt{1+{{y}^{2}}}=\lambda (x\sqrt{1+{{y}^{2}}}-y\sqrt{1+{{x}^{2}}})\] is

The degree of differential equation satisfying the relation\[\sqrt{1+{

1.	The degree of differential equation satisfying the relation\[\sqrt{1+{{x}^{2}}}+\sqrt{1+{{y}^{2}}}=\lambda (x\sqrt{1+{{y}^{2}}}-y\sqrt{1+{{x}^{2}}})\] is
A.	1
B.	2
C.	3
D.	4
Answer» B. 2

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The degree of differential equation satisfying the relation\[\sqrt{1+{{x}^{2}}}+\sqrt{1+{{y}^{2}}}=\lambda (x\sqrt{1+{{y}^{2}}}-y\sqrt{1+{{x}^{2}}})\] is

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