The deceleration experienced by a moving motorboat after its engine is cut off, is given by $$\frac{\text{dv}}{\text{dt}}\text{ = -K}{{\text{V}}^{3}}$$ where K is constant. If $${{V}_{0}}$$ is the magnitude of the velocity at cut-off, the magnitude of the velocity at a time t after the cut-off is

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The deceleration experienced by a moving motorboat after its engine is cut off, is given by $$\frac{\text{dv}}{\text{dt}}\text{ = -K}{{\text{V}}^{3}}$$  where K is constant. If $${{V}_{0}}$$ is the magnitude of the velocity at cut-off, the magnitude of the velocity at a time t after the cut-off is

TuteeHUB · Accepted Answer

NA

TuteeHUB · Answer

$$\frac{{{V}_{0}}}{\sqrt{\left( 2V_{0}^{2}Kt+1 \right)}}$$

TuteeHUB · Answer

$${{V}_{0}}{{e}^{-Kt}}$$

TuteeHUB · Answer

$${{V}_{0}}/2$$

TuteeHUB · Answer

$${{V}_{0}}$$

1.	The deceleration experienced by a moving motorboat after its engine is cut off, is given by \[\frac{\text{dv}}{\text{dt}}\text{ = -K}{{\text{V}}^{3}}\] where K is constant. If \[{{V}_{0}}\] is the magnitude of the velocity at cut-off, the magnitude of the velocity at a time t after the cut-off is
A.	\[\frac{{{V}_{0}}}{\sqrt{\left( 2V_{0}^{2}Kt+1 \right)}}\]
B.	\[{{V}_{0}}{{e}^{-Kt}}\]
C.	\[{{V}_{0}}/2\]
D.	\[{{V}_{0}}\]
Answer» E.

The deceleration experienced by a moving motorboat after its engine is cut off, is given by \[\frac{\text{dv}}{\text{dt}}\text{ = -K}{{\text{V}}^{3}}\] where K is constant. If \[{{V}_{0}}\] is the magnitude of the velocity at cut-off, the magnitude of the velocity at a time t after the cut-off is

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