The de-Broglie wavelength \[\lambda \]associated with an electron havi – McqOptions

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1.	The de-Broglie wavelength \[\lambda \]associated with an electron having kinetic energy E is given by the expression [MP PMT 1990; CPMT 1996]
A.	\[\frac{h}{\sqrt{2mE}}\]
B.	\[\frac{2h}{mE}\]
C.	\[2mhE\]
D.	\[\frac{2\sqrt{2mE}}{h}\]
Answer» B. \[\frac{2h}{mE}\]

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