1.

_ The C.O.P. of an absorption type refrigerator is given by (where T‚ÇÅ = Temperature at which the working substance receives heat, T‚ÇÇ = Temperature of cooling water, and T‚ÇÉ = Evaporator temperature)$?

A. [T‚ÇÅ (T‚ÇÇ - T‚ÇÉ)] / [T‚ÇÉ (T‚ÇÅ - T‚ÇÇ)]
B. [T‚ÇÉ (T‚ÇÅ - T‚ÇÇ)]/ [T‚ÇÅ (T‚ÇÇ - T‚ÇÉ)]
C. [T‚ÇÅ (T‚ÇÅ - T‚ÇÇ)] / [T‚ÇÉ (T‚ÇÇ - T‚ÇÉ)]
D. [T‚ÇÉ (T‚ÇÇ - T‚ÇÉ)] / [T‚ÇÅ (T‚ÇÅ - T‚ÇÇ)]
Answer» C. [T‚Äö√á√Ö (T‚Äö√á√Ö - T‚Äö√á√á)] / [T‚Äö√á√â (T‚Äö√á√á - T‚Äö√á√â)]


Discussion

No Comment Found