The coefficient of linear expansion of brass and steel are $${{\alpha }_{1}}$$ and $${{\alpha }_{2}}$$. If we take a brass rod of length $${{l}_{1}}$$ and steel rod of length $${{l}_{2}}$$ at 0°C, their difference in length $$({{l}_{2}}-{{l}_{1}})$$ will remain the same at a temperature if [EAMCET (Med.) 1995]

Question

The coefficient of linear expansion of brass and steel are $${{\alpha }_{1}}$$ and $${{\alpha }_{2}}$$. If we take a brass rod of length $${{l}_{1}}$$ and steel rod of length $${{l}_{2}}$$ at 0°C, their difference in length $$({{l}_{2}}-{{l}_{1}})$$ will remain the same at a temperature if        [EAMCET (Med.) 1995]

TuteeHUB · Accepted Answer

NA

TuteeHUB · Answer

$${{\alpha }_{1}}{{l}_{2}}={{\alpha }_{2}}{{l}_{1}}$$

TuteeHUB · Answer

$${{\alpha }_{1}}l_{2}^{2}={{\alpha }_{2}}l_{1}^{2}$$

TuteeHUB · Answer

$$\alpha _{1}^{2}{{l}_{1}}=\alpha _{2}^{2}{{l}_{2}}$$

TuteeHUB · Answer

$${{\alpha }_{1}}{{l}_{1}}={{\alpha }_{2}}{{l}_{2}}$$

1.	The coefficient of linear expansion of brass and steel are \[{{\alpha }_{1}}\] and \[{{\alpha }_{2}}\]. If we take a brass rod of length \[{{l}_{1}}\] and steel rod of length \[{{l}_{2}}\] at 0°C, their difference in length \[({{l}_{2}}-{{l}_{1}})\] will remain the same at a temperature if [EAMCET (Med.) 1995]
A.	\[{{\alpha }_{1}}{{l}_{2}}={{\alpha }_{2}}{{l}_{1}}\]
B.	\[{{\alpha }_{1}}l_{2}^{2}={{\alpha }_{2}}l_{1}^{2}\]
C.	\[\alpha _{1}^{2}{{l}_{1}}=\alpha _{2}^{2}{{l}_{2}}\]
D.	\[{{\alpha }_{1}}{{l}_{1}}={{\alpha }_{2}}{{l}_{2}}\]
Answer» E.

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