1.

The circuit shown here is used to compare the e.m.f. of two cells \[{{E}_{1}}\] and \[{{E}_{2}}({{E}_{1}}>{{E}_{2}})\]. The null point is at C when the galvanometer is connected to \[{{E}_{1}}\]. When the galvanometer is connected to \[{{E}_{2}}\], the null point will be  [MP PMT 1995]

A.                    To the left of C
B.                    To the right of C
C.                    At C itself
D.                    Nowhere on AB
Answer» B.                    To the right of C


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