The centre of a circle is (2, ?3) and the circumference is \[10\pi \]. Then the equation of the circle is [Kerala (Engg.) 2002]

\[{{x}^{2}}+{{y}^{2}}-4x-6y-12=0\]

\[{{x}^{2}}+{{y}^{2}}+4x+6y+12=0\]

\[{{x}^{2}}+{{y}^{2}}-4x+6y+12=0\]

\[{{x}^{2}}+{{y}^{2}}-4x+6y-12=0\]

The centre of a circle is (2, ?3) and the circumference is \[10\pi \].

1.	The centre of a circle is (2, ?3) and the circumference is \[10\pi \]. Then the equation of the circle is [Kerala (Engg.) 2002]
A.	\[{{x}^{2}}+{{y}^{2}}+4x+6y+12=0\]
B.	\[{{x}^{2}}+{{y}^{2}}-4x+6y+12=0\]
C.	\[{{x}^{2}}+{{y}^{2}}-4x+6y-12=0\]
D.	\[{{x}^{2}}+{{y}^{2}}-4x-6y-12=0\]
Answer» D. \[{{x}^{2}}+{{y}^{2}}-4x-6y-12=0\]

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The centre of a circle is (2, ?3) and the circumference is \[10\pi \]. Then the equation of the circle is [Kerala (Engg.) 2002]

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