The Cartesian equation of trajectory is (where u = Velocity of projection, ≈í¬± = Angle of projection, and x, y = Co-ordinates of any point on the trajectory after t seconds.)$?

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TuteeHUB · Accepted Answer

y = x. tan≈í¬± + (gx¬¨‚â§/2u¬¨‚â§ cos¬¨‚â§≈í¬±)

TuteeHUB · Answer

y = (gx¬¨‚â§/2u¬¨‚â§ cos¬¨‚â§≈í¬±) + x. tan≈í¬±

TuteeHUB · Answer

y = (gx¬¨‚â§/2u¬¨‚â§ cos¬¨‚â§≈í¬±) - x. tan≈í¬±

TuteeHUB · Answer

y = x. tan≈í¬± - (gx¬¨‚â§/2u¬¨‚â§ cos¬¨‚â§≈í¬±)

1.	The Cartesian equation of trajectory is (where u = Velocity of projection, ≈í¬± = Angle of projection, and x, y = Co-ordinates of any point on the trajectory after t seconds.)$?
A.	y = (gx¬¨‚â§/2u¬¨‚â§ cos¬¨‚â§≈í¬±) + x. tan≈í¬±
B.	y = (gx¬¨‚â§/2u¬¨‚â§ cos¬¨‚â§≈í¬±) - x. tan≈í¬±
C.	y = x. tan≈í¬± - (gx¬¨‚â§/2u¬¨‚â§ cos¬¨‚â§≈í¬±)
D.	y = x. tan≈í¬± + (gx¬¨‚â§/2u¬¨‚â§ cos¬¨‚â§≈í¬±)
Answer» D. y = x. tan≈í¬± + (gx¬¨‚â§/2u¬¨‚â§ cos¬¨‚â§≈í¬±)

The Cartesian equation of trajectory is (where u = Velocity of projection, ≈í¬± = Angle of projection, and x, y = Co-ordinates of any point on the trajectory after t seconds.)$?

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