MCQOPTIONS
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| 1. |
_ The C.O.P. of an absorption type refrigerator is given by (where T‚ÇÅ = Temperature at which the working substance receives heat, T‚ÇÇ = Temperature of cooling water, and T‚ÇÉ = Evaporator temperature)$? |
| A. | [T‚ÇÅ (T‚ÇÇ - T‚ÇÉ)] / [T‚ÇÉ (T‚ÇÅ - T‚ÇÇ)] |
| B. | [T‚ÇÉ (T‚ÇÅ - T‚ÇÇ)]/ [T‚ÇÅ (T‚ÇÇ - T‚ÇÉ)] |
| C. | [T‚ÇÅ (T‚ÇÅ - T‚ÇÇ)] / [T‚ÇÉ (T‚ÇÇ - T‚ÇÉ)] |
| D. | [T‚ÇÉ (T‚ÇÇ - T‚ÇÉ)] / [T‚ÇÅ (T‚ÇÅ - T‚ÇÇ)] |
| Answer» C. [T‚Äö√á√Ö (T‚Äö√á√Ö - T‚Äö√á√á)] / [T‚Äö√á√â (T‚Äö√á√á - T‚Äö√á√â)] | |