MCQOPTIONS
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| 1. |
The C.O.P. of a refrigerator working on a reversed Carnot cycle is (where T1 = Lowest absolute temperature, and T2 = Highest absolute temperature) |
| A. | T₁ / (T₂ - T₁) |
| B. | (T₂ - T₁)/T₁ |
| C. | (T₁ - T₂)/T₁ |
| D. | T₂/ (T₂ - T₁) |
| Answer» B. (T₂ - T₁)/T₁ | |