MCQOPTIONS
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| 1. |
The brown ring test for NO2 and \[N{{O}_{3}}^{-}\]is due to the formation of complex ion with the formula [KCET (Eng./Med.) 2000; Kerala PMT 2004] |
| A. | \[{{\left[ Fe{{\left( {{H}_{2}}O \right)}_{6}} \right]}^{2+}}\] |
| B. | \[{{\left[ Fe\left( NO \right)\text{ }{{\left( CN \right)}_{5}} \right]}^{2+}}\] |
| C. | \[{{\left[ Fe{{\left( {{H}_{2}}O \right)}_{5}}NO \right]}^{2+}}\] |
| D. | \[{{\left[ Fe\left( {{H}_{2}}O \right)\text{ }{{\left( NO \right)}_{5}} \right]}^{2+}}\] |
| Answer» D. \[{{\left[ Fe\left( {{H}_{2}}O \right)\text{ }{{\left( NO \right)}_{5}} \right]}^{2+}}\] | |