1.

The binding energy of deuteron \[\begin{matrix} 2 \\ 1 \\ \end{matrix}H\] is 1.112 Me V pen nucleon and an \[\alpha \]-particle \[\begin{matrix} 4 \\ 2 \\ \end{matrix}He\] has a binding energy of 7.047 Me V per nucleon. Then in the fusion reaction \[\begin{matrix} 2 \\ 1 \\ \end{matrix}He+\begin{matrix} 2 \\ 1 \\ \end{matrix}H\to \begin{matrix} 4 \\ 2 \\ \end{matrix}He+Q\], the energy Q released is

A. \[1\,MeV\]
B. \[11.9\,MeV\]
C. \[23.8\,MeV\]
D. \[931\,MeV\]
Answer» D. \[931\,MeV\]


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