MCQOPTIONS
Saved Bookmarks
| 1. |
The binding energy of deuteron \[\begin{matrix} 2 \\ 1 \\ \end{matrix}H\] is 1.112 Me V pen nucleon and an \[\alpha \]-particle \[\begin{matrix} 4 \\ 2 \\ \end{matrix}He\] has a binding energy of 7.047 Me V per nucleon. Then in the fusion reaction \[\begin{matrix} 2 \\ 1 \\ \end{matrix}He+\begin{matrix} 2 \\ 1 \\ \end{matrix}H\to \begin{matrix} 4 \\ 2 \\ \end{matrix}He+Q\], the energy Q released is |
| A. | \[1\,MeV\] |
| B. | \[11.9\,MeV\] |
| C. | \[23.8\,MeV\] |
| D. | \[931\,MeV\] |
| Answer» D. \[931\,MeV\] | |