1.

The asymptotes and the break point coincide at s = 2. The transfer function can be

A. <table><tr><td style="border-bottom:1px solid #000000;vertical-align:bottom;padding-bottom:2px;"><center>K(s + 2)</center></td></tr><tr><td style="text-align: center;">(s + 1)(s + 2)</td></tr></table>
B. <table><tr><td style="border-bottom:1px solid #000000;vertical-align:bottom;padding-bottom:2px;"><center>K(s + 2)</center></td></tr><tr><td style="text-align: center;">(s + 1)(s + 3)</td></tr></table>
C. <table><tr><td style="border-bottom:1px solid #000000;vertical-align:bottom;padding-bottom:2px;"><center>K</center></td></tr><tr><td style="text-align: center;">(s + 1)(s + 2)(s + 3)</td></tr></table>
D. <table><tr><td style="border-bottom:1px solid #000000;vertical-align:bottom;padding-bottom:2px;"><center>K</center></td></tr><tr><td style="text-align: center;">(s + 2)<sup>3</sup></td></tr></table>
Answer» E.


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