The area of the triangle formed by the lines \[y={{m}_{1}}x+{{c}_{1}},\,\] \[y={{m}_{2}}x+{{c}_{2}}\] and \[x=0\]is

\[\frac{{{({{c}_{1}}-{{c}_{2}})}^{2}}}{({{m}_{1}}-{{m}_{2}})}\]

\[\frac{1}{2}\frac{{{({{c}_{1}}+{{c}_{2}})}^{2}}}{({{m}_{1}}-{{m}_{2}})}\]

\[\frac{1}{2}\frac{{{({{c}_{1}}-{{c}_{2}})}^{2}}}{({{m}_{1}}+{{m}_{2}})}\]

\[\frac{1}{2}\frac{{{({{c}_{1}}-{{c}_{2}})}^{2}}}{({{m}_{1}}-{{m}_{2}})}\]

The area of the triangle formed by the lines \[y={{m}_{1}}x+{{c}_{1}},

1.	The area of the triangle formed by the lines \[y={{m}_{1}}x+{{c}_{1}},\,\] \[y={{m}_{2}}x+{{c}_{2}}\] and \[x=0\]is
A.	\[\frac{1}{2}\frac{{{({{c}_{1}}+{{c}_{2}})}^{2}}}{({{m}_{1}}-{{m}_{2}})}\]
B.	\[\frac{1}{2}\frac{{{({{c}_{1}}-{{c}_{2}})}^{2}}}{({{m}_{1}}+{{m}_{2}})}\]
C.	\[\frac{1}{2}\frac{{{({{c}_{1}}-{{c}_{2}})}^{2}}}{({{m}_{1}}-{{m}_{2}})}\]
D.	\[\frac{{{({{c}_{1}}-{{c}_{2}})}^{2}}}{({{m}_{1}}-{{m}_{2}})}\]
Answer» D. \[\frac{{{({{c}_{1}}-{{c}_{2}})}^{2}}}{({{m}_{1}}-{{m}_{2}})}\]

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The area of the triangle formed by the lines \[y={{m}_{1}}x+{{c}_{1}},\,\] \[y={{m}_{2}}x+{{c}_{2}}\] and \[x=0\]is

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