1.

The area enclosed by the curve \[y=\sqrt{4-{{x}^{2}}},\] \[y\ge \sqrt{2}\sin \left( \frac{x\pi }{2\sqrt{2}} \right)\], and the x-axis is divided by the y-axis in the ratio

A. \[\frac{{{\pi }^{2}}-8}{{{\pi }^{2}}+8}\]       
B. \[\frac{{{\pi }^{2}}-4}{{{\pi }^{2}}+4}\]
C. \[\frac{\pi -4}{\pi -4}\]   
D. \[\frac{2{{\pi }^{2}}}{2\pi +{{\pi }^{2}}-8}\]
Answer» E.


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