The area bounded by the x-axis, the curve \[y=f(x)\] and the lines \[x=1,\text{ }x=b,\] is equal to\[\sqrt{{{b}^{2}}+1}-\sqrt{2}\] for all \[b>1\], then f(x) is

\[\frac{x}{\sqrt{1+{{x}^{2}}}}\]

The area bounded by the x-axis, the curve \[y=f(x)\] and the lines \[x

1.	The area bounded by the x-axis, the curve \[y=f(x)\] and the lines \[x=1,\text{ }x=b,\] is equal to\[\sqrt{{{b}^{2}}+1}-\sqrt{2}\] for all \[b>1\], then f(x) is
A.	\[\sqrt{x-1}\]
B.	\[\sqrt{x+1}\]
C.	\[\sqrt{{{x}^{2}}+1}\]
D.	\[\frac{x}{\sqrt{1+{{x}^{2}}}}\]
Answer» E.

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The area bounded by the x-axis, the curve \[y=f(x)\] and the lines \[x=1,\text{ }x=b,\] is equal to\[\sqrt{{{b}^{2}}+1}-\sqrt{2}\] for all \[b>1\], then f(x) is

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