The angle which the velocity vector of a projectile thrown with a velocity v at an angle \[\theta \] to the horizontal will make with the horizontal after time t of its being thrown up is:

\[{{\tan }^{-1}}\left( \theta /\text{t} \right)\]

\[{{\tan }^{-1}}\left( \frac{\text{v cos}\theta }{\text{v sin}\theta -\text{gt}} \right)\]

\[{{\tan }^{-1}}\left( \frac{\text{v sin}\theta -\text{gt}}{\text{v cos}\theta } \right)\]

The angle which the velocity vector of a projectile thrown with a velo

1.	The angle which the velocity vector of a projectile thrown with a velocity v at an angle \[\theta \] to the horizontal will make with the horizontal after time t of its being thrown up is:
A.	\[\theta \]
B.	\[{{\tan }^{-1}}\left( \theta /\text{t} \right)\]
C.	\[{{\tan }^{-1}}\left( \frac{\text{v cos}\theta }{\text{v sin}\theta -\text{gt}} \right)\]
D.	\[{{\tan }^{-1}}\left( \frac{\text{v sin}\theta -\text{gt}}{\text{v cos}\theta } \right)\]
Answer» E.