The amount of Zn (atomic weight = 65) required to form 224 c.c. of H� – McqOptions

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1.	The amount of Zn (atomic weight = 65) required to form 224 c.c. of H‚Äö√á√á at N.T.P. on treatment with dilute H‚Äö√á√áSO‚Äö√á√ë will be __________ gm.#
A.	0.065
B.	0.65
C.	6.5
D.	65
Answer» C. 6.5

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