\[\tan \left[ \frac{\pi }{4}+\frac{1}{2}{{\cos }^{-1}}\frac{a}{b} \right]+\tan \left[ \frac{\pi }{4}-\frac{1}{2}{{\cos }^{-1}}\frac{a}{b} \right]=\] [MP PET 1999]

\[\tan \left[ \frac{\pi }{4}+\frac{1}{2}{{\cos }^{-1}}\frac{a}{b} \r

1.	\[\tan \left[ \frac{\pi }{4}+\frac{1}{2}{{\cos }^{-1}}\frac{a}{b} \right]+\tan \left[ \frac{\pi }{4}-\frac{1}{2}{{\cos }^{-1}}\frac{a}{b} \right]=\] [MP PET 1999]
A.	\[\frac{2a}{b}\]
B.	\[\frac{2b}{a}\]
C.	\[\frac{a}{b}\]
D.	\[\frac{b}{a}\]
Answer» C. \[\frac{a}{b}\]

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\[\tan \left[ \frac{\pi }{4}+\frac{1}{2}{{\cos }^{-1}}\frac{a}{b} \right]+\tan \left[ \frac{\pi }{4}-\frac{1}{2}{{\cos }^{-1}}\frac{a}{b} \right]=\] [MP PET 1999]

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