\[\tan \left[ \frac{1}{2}{{\sin }^{-1}}\left( \frac{2a}{1+{{a}^{2}}} \right)+\frac{1}{2}{{\cos }^{-1}}\left( \frac{1-{{a}^{2}}}{1+{{a}^{2}}} \right) \right]=\]

\[\frac{1-{{a}^{2}}}{1+{{a}^{2}}}\]

\[\tan \left[ \frac{1}{2}{{\sin }^{-1}}\left( \frac{2a}{1+{{a}^{2}}} \

1.	\[\tan \left[ \frac{1}{2}{{\sin }^{-1}}\left( \frac{2a}{1+{{a}^{2}}} \right)+\frac{1}{2}{{\cos }^{-1}}\left( \frac{1-{{a}^{2}}}{1+{{a}^{2}}} \right) \right]=\]
A.	\[\frac{2a}{1+{{a}^{2}}}\]
B.	\[\frac{1-{{a}^{2}}}{1+{{a}^{2}}}\]
C.	\[\frac{2a}{1-{{a}^{2}}}\]
D.	None of these
Answer» D. None of these

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\[\tan \left[ \frac{1}{2}{{\sin }^{-1}}\left( \frac{2a}{1+{{a}^{2}}} \right)+\frac{1}{2}{{\cos }^{-1}}\left( \frac{1-{{a}^{2}}}{1+{{a}^{2}}} \right) \right]=\]

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