\[\tan 3A-\tan 2A-\tan A=\] [MNR 1982; Pb. CET 1991]

1.	\[\tan 3A-\tan 2A-\tan A=\] [MNR 1982; Pb. CET 1991]
A.	\[\tan 3A\tan 2A\tan A\]
B.	\[-\tan 3A\tan 2A\tan A\]
C.	\[\tan A\tan 2A-\tan 2A\tan 3A-\tan 3A\tan A\]
D.	None of these
Answer» B. \[-\tan 3A\tan 2A\tan A\]

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\[\tan 3A-\tan 2A-\tan A=\] [MNR 1982; Pb. CET 1991]

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