\[{{\tan }^{-1}}\left( \frac{\sqrt{1+{{x}^{2}}}-1}{x} \right)=\]

1.	\[{{\tan }^{-1}}\left( \frac{\sqrt{1+{{x}^{2}}}-1}{x} \right)=\]
A.	\[{{\tan }^{-1}}x\]
B.	\[\frac{1}{2}{{\tan }^{-1}}x\]
C.	\[2{{\tan }^{-1}}x\]
D.	None of these
Answer» C. \[2{{\tan }^{-1}}x\]

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\[{{\tan }^{-1}}\left( \frac{\sqrt{1+{{x}^{2}}}-1}{x} \right)=\]

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