\[{{\tan }^{-1}}\left[ \frac{\cos x}{1+\sin x} \right]=\]

1.	\[{{\tan }^{-1}}\left[ \frac{\cos x}{1+\sin x} \right]=\]
A.	\[\frac{\pi }{4}-\frac{x}{2}\]
B.	\[\frac{\pi }{4}+\frac{x}{2}\]
C.	\[\frac{x}{2}\]
D.	\[\frac{\pi }{4}-x\]
Answer» B. \[\frac{\pi }{4}+\frac{x}{2}\]

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\[{{\tan }^{-1}}\left[ \frac{\cos x}{1+\sin x} \right]=\]

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