1.

\[{{\tan }^{-1}}\left( \frac{1}{4} \right)+{{\tan }^{-1}}\left( \frac{2}{9} \right)=\]   [EAMCET 1994]

A. \[\frac{1}{2}{{\cos }^{-1}}\left( \frac{3}{5} \right)\]
B. \[\frac{1}{2}{{\sin }^{-1}}\left( \frac{3}{5} \right)\]
C. \[\frac{1}{2}{{\tan }^{-1}}\left( \frac{3}{5} \right)\]
D. \[{{\tan }^{-1}}\left( \frac{1}{2} \right)\]
Answer» B. \[\frac{1}{2}{{\sin }^{-1}}\left( \frac{3}{5} \right)\]


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