\[{{\tan }^{-1}}\frac{x}{\sqrt{{{a}^{2}}-{{x}^{2}}}}=\]

1.	\[{{\tan }^{-1}}\frac{x}{\sqrt{{{a}^{2}}-{{x}^{2}}}}=\]
A.	\[\frac{1}{a}{{\sin }^{-1}}\left( \frac{x}{a} \right)\]
B.	\[a{{\sin }^{-1}}\left( \frac{x}{a} \right)\]
C.	\[{{\sin }^{-1}}\left( \frac{x}{a} \right)\]
D.	\[{{\sin }^{-1}}\left( \frac{a}{x} \right)\]
Answer» D. \[{{\sin }^{-1}}\left( \frac{a}{x} \right)\]

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\[{{\tan }^{-1}}\frac{x}{\sqrt{{{a}^{2}}-{{x}^{2}}}}=\]

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