\[{{\tan }^{-1}}\frac{{{c}_{1}}x-y}{{{c}_{1}}y+x}+{{\tan }^{-1}}\frac{{{c}_{2}}-{{c}_{1}}}{1+{{c}_{2}}{{c}_{1}}}+\]\[{{\tan }^{-1}}\frac{{{c}_{3}}-{{c}_{2}}}{1+{{c}_{3}}{{c}_{2}}}+...+{{\tan }^{-1}}\frac{1}{{{c}_{n}}}=\]

\[{{\tan }^{-1}}\frac{{{c}_{1}}x-y}{{{c}_{1}}y+x}+{{\tan }^{-1}}\frac{

1.	\[{{\tan }^{-1}}\frac{{{c}_{1}}x-y}{{{c}_{1}}y+x}+{{\tan }^{-1}}\frac{{{c}_{2}}-{{c}_{1}}}{1+{{c}_{2}}{{c}_{1}}}+\]\[{{\tan }^{-1}}\frac{{{c}_{3}}-{{c}_{2}}}{1+{{c}_{3}}{{c}_{2}}}+...+{{\tan }^{-1}}\frac{1}{{{c}_{n}}}=\]
A.	\[{{\tan }^{-1}}\frac{y}{x}\]
B.	\[{{\tan }^{-1}}yx\]
C.	\[{{\tan }^{-1}}\frac{x}{y}\]
D.	\[{{\tan }^{-1}}(x-y)\]
Answer» D. \[{{\tan }^{-1}}(x-y)\]

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\[{{\tan }^{-1}}\frac{{{c}_{1}}x-y}{{{c}_{1}}y+x}+{{\tan }^{-1}}\frac{{{c}_{2}}-{{c}_{1}}}{1+{{c}_{2}}{{c}_{1}}}+\]\[{{\tan }^{-1}}\frac{{{c}_{3}}-{{c}_{2}}}{1+{{c}_{3}}{{c}_{2}}}+...+{{\tan }^{-1}}\frac{1}{{{c}_{n}}}=\]

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