\[{{\tan }^{-1}}\frac{3}{4}+{{\tan }^{-1}}\frac{3}{5}-{{\tan }^{-1}}\frac{8}{19}=\] [AMU 1976, 77]

\[{{\tan }^{-1}}\frac{3}{4}+{{\tan }^{-1}}\frac{3}{5}-{{\tan }^{-1}}\f

1.	\[{{\tan }^{-1}}\frac{3}{4}+{{\tan }^{-1}}\frac{3}{5}-{{\tan }^{-1}}\frac{8}{19}=\] [AMU 1976, 77]
A.	\[\frac{\pi }{4}\]
B.	\[\frac{\pi }{3}\]
C.	\[\frac{\pi }{6}\]
D.	None of these
Answer» B. \[\frac{\pi }{3}\]

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\[{{\tan }^{-1}}\frac{3}{4}+{{\tan }^{-1}}\frac{3}{5}-{{\tan }^{-1}}\frac{8}{19}=\] [AMU 1976, 77]

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