Suppose\[f(x)={{e}^{ax}}+{{e}^{bx}}\], where\[a\ne b\], and that \[f{{\,}^{n}}(x)-2f'(x)-15f(x)=0\] for all x. Then the product ab is

Suppose\[f(x)={{e}^{ax}}+{{e}^{bx}}\], where\[a\ne b\], and that \[f{{

1.	Suppose\[f(x)={{e}^{ax}}+{{e}^{bx}}\], where\[a\ne b\], and that \[f{{\,}^{n}}(x)-2f'(x)-15f(x)=0\] for all x. Then the product ab is
A.	25
B.	9
C.	-15
D.	-9
Answer» D. -9

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Suppose\[f(x)={{e}^{ax}}+{{e}^{bx}}\], where\[a\ne b\], and that \[f{{\,}^{n}}(x)-2f'(x)-15f(x)=0\] for all x. Then the product ab is

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