Suppose \[f:[2,\ 2]\to R\] is defined by \[f(x)=\left\{ \begin{align} & -1\,\,\,\,\,\,\,\,\,\,\,\,\,\text{for}\ -2\le x\le 0 \\ & x-1\ \ \ \ \ \text{for}\ 0\le x\le 2 \\ \end{align} \right.\], then \[\{x\in (-2,\ 2):x\le 0\] and \[f(|x|)=x\}=\] [EAMCET 2003]

Suppose \[f:[2,\ 2]\to R\] is defined by \[f(x)=\left\{ \begin{align

1.	Suppose \[f:[2,\ 2]\to R\] is defined by \[f(x)=\left\{ \begin{align} & -1\,\,\,\,\,\,\,\,\,\,\,\,\,\text{for}\ -2\le x\le 0 \\ & x-1\ \ \ \ \ \text{for}\ 0\le x\le 2 \\ \end{align} \right.\], then \[\{x\in (-2,\ 2):x\le 0\] and \[f(\|x\|)=x\}=\] [EAMCET 2003]
A.	\[\{-1\}\]
B.	{0}
C.	\[\{-1/2\}\]
D.	\[\varphi \]
Answer» D. \[\varphi \]

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Suppose \[f:[2,\ 2]\to R\] is defined by \[f(x)=\left\{ \begin{align} & -1\,\,\,\,\,\,\,\,\,\,\,\,\,\text{for}\ -2\le x\le 0 \\ & x-1\ \ \ \ \ \text{for}\ 0\le x\le 2 \\ \end{align} \right.\], then \[\{x\in (-2,\ 2):x\le 0\] and \[f(|x|)=x\}=\] [EAMCET 2003]

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