Sum of roots is \[-1\] and sum of their reciprocals is \[\frac{1}{6}\], then equation is [Karnataka CET 1998]

Sum of roots is \[-1\] and sum of their reciprocals is \[\frac{1}{6}\]

1.	Sum of roots is \[-1\] and sum of their reciprocals is \[\frac{1}{6}\], then equation is [Karnataka CET 1998]
A.	\[{{x}^{2}}+x-6=0\]
B.	\[{{x}^{2}}-x+6=0\]
C.	\[6{{x}^{2}}+x+1=0\]
D.	\[{{x}^{2}}-6x+1=0\]
Answer» B. \[{{x}^{2}}-x+6=0\]

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Sum of roots is \[-1\] and sum of their reciprocals is \[\frac{1}{6}\], then equation is [Karnataka CET 1998]

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