MCQOPTIONS
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| 1. |
Sum of first three ionization energies of Al is \[53.0\text{ }eV\text{ }ato{{m}^{-1}}\] and the sum of first two ionization energies of Na is \[52.2\text{ }eV\text{ }ato{{m}^{-1}}.\] Out of Al(III) and Na(II) |
| A. | Na (II) is more stable than Al (III) |
| B. | Al (III) is more stable than Na (II) |
| C. | Both are equally stable |
| D. | Both are equally unstable |
| Answer» C. Both are equally stable | |