1.

\[\sum\limits_{r=1}^{n}{{{\sin }^{-1}}}\left( \frac{\sqrt{r}-\sqrt{r-1}}{\sqrt{r(r+1)}} \right)\] is equal to

A. \[{{\tan }^{-1}}(\sqrt{n})-\frac{\pi }{4}\]
B. \[{{\tan }^{-1}}(\sqrt{n+1})-\frac{\pi }{4}\]
C. \[{{\tan }^{-1}}(\sqrt{n})\]
D. \[{{\tan }^{-1}}(\sqrt{n+1})\]
Answer» D. \[{{\tan }^{-1}}(\sqrt{n+1})\]


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