\[\sum\limits_{m=1}^{n}{{{m}^{2}}}\] is equal to [RPET 1995]

1.	\[\sum\limits_{m=1}^{n}{{{m}^{2}}}\] is equal to [RPET 1995]
A.	\[\frac{m(m+1)}{2}\]
B.	\[\frac{m(m+1)(2m+1)}{6}\]
C.	\[\frac{n(n+1)(2n+1)}{6}\]
D.	\[\frac{n(n+1)}{2}\]
Answer» D. \[\frac{n(n+1)}{2}\]

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\[\sum\limits_{m=1}^{n}{{{m}^{2}}}\] is equal to [RPET 1995]

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