\[\sqrt{\frac{1-\sin A}{1+\sin A}}=\]

1.	\[\sqrt{\frac{1-\sin A}{1+\sin A}}=\]
A.	\[\sec A+\tan A\]
B.	\[\tan \left( \frac{\pi }{4}-A \right)\]
C.	\[\tan \left( \frac{\pi }{4}+\frac{A}{2} \right)\]
D.	\[\tan \left( \frac{\pi }{4}-\frac{A}{2} \right)\]
Answer» E.

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\[\sqrt{\frac{1-\sin A}{1+\sin A}}=\]

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