Solution of \[ydx-xdy={{x}^{2}}ydx\]is [MP PET 1999]

1.	Solution of \[ydx-xdy={{x}^{2}}ydx\]is [MP PET 1999]
A.	\[y{{e}^{{{x}^{2}}}}=c{{x}^{2}}\]
B.	\[y{{e}^{-{{x}^{2}}}}=c{{x}^{2}}\]
C.	\[{{y}^{2}}{{e}^{{{x}^{2}}}}=c{{x}^{2}}\]
D.	\[{{y}^{2}}{{e}^{-{{x}^{2}}}}=c{{x}^{2}}\]
Answer» D. \[{{y}^{2}}{{e}^{-{{x}^{2}}}}=c{{x}^{2}}\]

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Solution of \[ydx-xdy={{x}^{2}}ydx\]is [MP PET 1999]

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