1.

Solution of the differential equation\[\frac{dx}{dy}-\frac{x\,\,\log \,\,x}{1+\log \,\,x}=\frac{{{e}^{y}}}{1+\log \,\,x'}\] if \[y(1)=0\], is

A. \[{{x}^{x}}={{e}^{y{{e}^{y}}}}\]
B. \[{{e}^{y}}={{x}^{{{e}^{y}}}}\]
C. \[{{x}^{x}}=y{{e}^{^{y}}}\]
D. None of these
Answer» B. \[{{e}^{y}}={{x}^{{{e}^{y}}}}\]


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