MCQOPTIONS
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| 1. |
Solution of the differential equation\[\frac{dx}{dy}-\frac{x\,\,\log \,\,x}{1+\log \,\,x}=\frac{{{e}^{y}}}{1+\log \,\,x'}\] if \[y(1)=0\], is |
| A. | \[{{x}^{x}}={{e}^{y{{e}^{y}}}}\] |
| B. | \[{{e}^{y}}={{x}^{{{e}^{y}}}}\] |
| C. | \[{{x}^{x}}=y{{e}^{^{y}}}\] |
| D. | None of these |
| Answer» B. \[{{e}^{y}}={{x}^{{{e}^{y}}}}\] | |