Solution of \[\frac{dy}{dx}=\frac{x\log {{x}^{2}}+x}{\sin y+y\,\,\cos y}\] is [EAMCET 2003]

Solution of \[\frac{dy}{dx}=\frac{x\log {{x}^{2}}+x}{\sin y+y\,\,\cos

1.	Solution of \[\frac{dy}{dx}=\frac{x\log {{x}^{2}}+x}{\sin y+y\,\,\cos y}\] is [EAMCET 2003]
A.	\[y\sin y={{x}^{2}}\log x+c\]
B.	\[y\sin y={{x}^{2}}+c\]
C.	\[y\sin y={{x}^{2}}+\log x+c\]
D.	\[y\sin y=x\log x+c\]
Answer» B. \[y\sin y={{x}^{2}}+c\]

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