Solution of differential equation \[\frac{dy}{dx}=\frac{y-x}{y+x}\]is

1.	Solution of differential equation \[\frac{dy}{dx}=\frac{y-x}{y+x}\]is [MP PET 1997]
A.	\[{{\log }_{e}}({{x}^{2}}+{{y}^{2}})+2{{\tan }^{-1}}\frac{y}{x}+c=0\]
B.	\[\frac{{{y}^{2}}}{2}+xy=xy-\frac{{{x}^{2}}}{2}+c\]
C.	\[\left( 1+\frac{x}{y} \right)\text{ }y=\left( 1-\frac{x}{y} \right)\text{ }x+c\]
D.	\[y=x-2{{\log }_{e}}y+c\]
Answer» B. \[\frac{{{y}^{2}}}{2}+xy=xy-\frac{{{x}^{2}}}{2}+c\]

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Solution of differential equation \[\frac{dy}{dx}=\frac{y-x}{y+x}\]is [MP PET 1997]

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